Compare sequences, interpret tree relationships and use a stated clock rate.
Method and worked examples
Comparing homologous DNA or protein sequences helps estimate evolutionary relatedness. With suitable comparisons, fewer differences generally support a more recent common ancestor. DNA–DNA hybridisation compares how well strands from different sources pair; greater complementarity can increase hybrid stability under comparable conditions. Ribosomal RNA gene sequences are especially useful for comparisons involving prokaryotes.
A phylogenetic tree represents branching relationships. Relatedness depends on the most recent shared branch point, not how close names are printed on the page. Rotating branches at a node does not change ancestry. A molecular-clock calculation requires a stated rate and a clear definition of whether that rate applies per lineage or to total pairwise divergence. Clock estimates depend on assumptions; rates can differ among genes and lineages.
Example 1
Sequences are ACGTAC and ACGTTC. How many positions differ?
Only position 5 differs, so there is 1 difference across 6 aligned bases.
Example 2
Two lineages each accumulate 1 difference per million years. Pairwise divergence is 10 differences. Find separation time.
Combined rate =2 differences per million years. Time =210=5 million years.
Watch out:Use the most recent common ancestor in the branching pattern, not printed distance.
Molecular evidence and relationships | Year 12 Biology | Ascent Arcade