Read heating data and combine warming with phase changes.
Method and worked examples
Break a heating process into distinct stages. On a sloping section of a temperature–time graph, use Q= mcΔT if the sample remains in one state. On a plateau at a phase transition, use Q=mL. Add the energies for a multistage process. A time interval on its own is not a temperature change; check which axis is horizontal before reading a slope.
For constant absorbed power P, each stage takes t=PQ. A larger heat capacity gives a shallower temperature–time slope because dtdT=mcP. A longer phase-change plateau means more absorbed energy if power is unchanged. State whether the model neglects energy absorbed by the container and energy escaping to the surroundings; these terms alter the relation between electrical input and sample energy.
Example 1
Warm 0.10kg of ice from −10∘C to 0∘C, then melt it. Use cice =(kgK)2100J,Lf=kg334000J and no losses.
Warm ice: Q1=0.10×2100×10=2100J. Melt: Q2=0.10×334000=33400J. Total =35500J.
Example 2
An ideal 200W heater supplies a phase-change plateau for 50s. Find energy absorbed.
Q=Pt=200×50=10000J. Temperature can remain constant throughout this non-zero transfer.
Watch out:Separate warming and phase-change stages; the phase-change energy is mL and is not included by a zero ΔT.
16. Heating curves and combined energy steps | Year 11 Physics | Ascent Arcade