Connect force through displacement with changes in kinetic and gravitational potential energy.
Method and worked examples
For a constant force parallel to displacement, work is W= Fs. A force opposing displacement does negative work; a perpendicular force does zero work. More generally W= Fs cosθ, where θ is the angle between force and displacement. Work transfers energy, with joules equivalent to newton-metres. Net work on a particle equals its change in kinetic energy.
Kinetic energy is Ek= ½mv2, so it depends on speed squared and is never negative. Near Earth, a gravitational potential-energy change is ΔEp= mgΔh with approximately constant g. Choose a reference height, but remember that physical transfers depend on height differences. Distinguish the work of one force from the net work of all forces.
Example 1
A constant 12N force acts along a 3.0m displacement. Find work.
W=Fs=12×3.0=36J. The force and displacement are parallel.
Example 2
Raise a 2.0kg mass through 1.5m. Use g=kg9.8N. Find gravitational potential-energy increase.
ΔEp= mgΔh=2.0×9.8×1.5=29.4J.
Watch out:Kinetic energy is proportional to speed squared, so doubling speed multiplies it by four at fixed mass.
17. Work and mechanical energy | Year 11 Physics | Ascent Arcade