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Year 11 · Practical trigonometry · 25 min

Non-right-triangle surveying/navigation problems

Build and solve triangle models for surveying, inaccessible distances and routes.

01 / LEARN

The idea, step by step

Translate the measurements into a model

A baseline and two sightings can form a non-right triangle. Label the stations, measured angles and required side, then mark opposite pairs.

Directions measured at different stations need care: reverse a baseline bearing when necessary. A difference between arbitrary bearing numbers need not be an interior angle.

Select and explain a sequence of methods

Use a sine rule with a complete opposite pair; use cosine rule for SAS or SSS. Some problems need an angle sum, then a side, then an area or perpendicular distance.

Say whether the result is horizontal, sloping or direct distance. Note assumptions such as level ground, straight routes and negligible instrument height; match the final units to the question.

A common trap

Assuming a navigation triangle is right-angled because the sketch looks that way.

Instead: Use a right-triangle method only when a right angle is stated or justified.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example 1

Survey stations A and B are 30 m apart. A tree T lies on one side of AB with angle TAB=55° and TBA=70°. Find AT.

  1. Angle T=180°−55°−70°=55°.
  2. AB is opposite T and AT is opposite B.
  3. AT=30sin70°/sin55°.
34.4 m
Example 2

Worked example 2

Paths from a gate follow bearings 040° and 115°. P is 18 m along the first and Q is 25 m along the second. Find PQ.

  1. The included angle at the gate is 115°−40°=75°.
  2. Use SAS cosine rule.
  3. PQ²=18²+25²−2×18×25cos75°.
26.8 m

Check your understanding

Two routes from the same point have bearings 025° and 100°. Find their smaller included angle.

Show answer

75°

100°−25°=75° from the same north line.

03 / WORKSHEET

Your turn

6 questions · 17 marks · Work at your own pace.

Read the questions online
  1. A 40 m baseline AB has a point P to one side. Angle PAB=35° and PBA=65°. Find AP.
    3 marks
  2. Routes from a depot have bearings 020° and 110°. Points 12 km and 16 km along them are joined. Find the joining distance.
    2 marks
  3. A triangular plot has sides 30 m and 42 m enclosing 55°. Find its area to one decimal place.
    2 marks
  4. Two ground-level observers and the tower base lie on the same straight level line. Both observers are on one side of the tower, 20 m apart. The nearer elevation is 60° and the farther 30°. Find the tower height.
    4 marks
  5. P is 20 km from O on bearing 350°. Q is 15 km from O on bearing 030°. Find the smaller angle POQ and PQ.
    3 marks
  6. A survey assumes level ground, but a measured baseline slopes up a hill. Explain why its sloping length cannot automatically replace a horizontal baseline.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. A 40 m baseline AB has a point P to one side. Angle PAB=35° and PBA=65°. Find AP.
    3 marks

    Angle P=80°.

    AP=40sin65°/sin80°.

    36.8 m
  2. Routes from a depot have bearings 020° and 110°. Points 12 km and 16 km along them are joined. Find the joining distance.
    2 marks

    The included angle is 90°.

    d=√(12²+16²)=20 km.

    20 km
  3. A triangular plot has sides 30 m and 42 m enclosing 55°. Find its area to one decimal place.
    2 marks

    K=½×30×42sin55°.

    K=630sin55° square metres.

    516.1 m²
  4. Two ground-level observers and the tower base lie on the same straight level line. Both observers are on one side of the tower, 20 m apart. The nearer elevation is 60° and the farther 30°. Find the tower height.
    4 marks

    Let x be the nearer horizontal distance. h=x tan60°=(x+20)tan30°.

    Solve to obtain x=10 m.

    h=10√3 m.

    17.3 m
  5. P is 20 km from O on bearing 350°. Q is 15 km from O on bearing 030°. Find the smaller angle POQ and PQ.
    3 marks

    The angle crosses north: 10°+30°=40°.

    PQ²=20²+15²−2×20×15cos40°.

    40°; PQ≈12.9 km
  6. A survey assumes level ground, but a measured baseline slopes up a hill. Explain why its sloping length cannot automatically replace a horizontal baseline.
    3 marks

    A horizontal triangle uses horizontal distances.

    Using an uncorrected sloping distance changes the geometry.

    Its horizontal projection is shorter; the model needs a slope correction or additional height/angle information.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 General Mathematics: practical trigonometry, including similarity, right triangles, triangle area, sine/cosine rules and contextual interpretation.

Official curriculum source ↗
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