ASCENTLEARNING
Join a weekly class
Skip to learning content
Year 12 · Financial mathematics · 18 min

Compound-interest revision

Build a compound-interest model using a rate and a number of matching periods, then interpret the balance and interest separately.

01 / LEARN

The idea, step by step

The balance grows by a multiplier

If the balance earns interest and that interest remains in the account, the next period starts with a larger amount. With a constant periodic rate i, each step multiplies the balance by 1+i. A rate of 4% means i=0.04, not 4. State when interest is credited before counting periods.

The model assumes no deposits, withdrawals, fees or rate changes. When any of those occur, use a recurrence or divide the calculation into stages. Keep the unrounded calculator value until the final money answer.

Bn=P⁢(1+i)n

Read the result correctly

The future balance includes the original principal. Interest earned is Bn−P; it is not Bn itself. A decreasing value can use the same multiplier idea, with 1−d for a depreciation rate d.

When reversing the model, divide by the complete growth factor. The rate and period count must match: monthly interest over three years requires 36 periods. A quoted annual nominal rate needs conversion to its stated compounding frequency.

A common trap

Using the annual rate with a monthly period count.

Instead: First convert the rate to one period, then count those same periods.

02 / WORKED EXAMPLES

See the thinking

Example 1

Build the model

AUD 1,200 earns 4% interest annually for 3 years. Find the final balance and total interest.

  1. Use i=0.04 and n=3.
  2. Balance = 1200⁢(1.04)3 = AUD 1,349.84.
  3. Subtract AUD 1,200 to find the interest.
AUD 1,349.84; interest AUD 149.84
Example 2

Use the model to make a decision

A tool costing AUD 2,500 loses 12% of its value each year. Estimate its value after 4 years.

  1. Use the multiplier 0.88, because 88% of the value remains each year.
  2. Value = 2500⁢(0.88)4 = AUD 1,499.24.
AUD 1,499.24

Check your understanding

AUD 900 grows to AUD 1,050. What interest has been earned?

Show answer

AUD 150.00

Interest = final balance − principal. 1050−900=150.

03 / WORKSHEET

Your turn

6 questions · 18 marks · Work at your own pace.

Read the questions online
  1. Find the balance of AUD 3,400 after 5 years at 3.5% compounded annually.
    3 marks
  2. AUD 900 grows to AUD 1,050. What interest has been earned?
    3 marks
  3. An account reaches AUD 8,000 after 6 years at 5% compounded annually. Find its original principal.
    3 marks
  4. AUD 2,000 earns a nominal annual rate of 6%, compounded monthly, for 2 years. Find the balance.
    3 marks
  5. A model uses B=6000⁢(1.02)8. State the periodic rate and the number of periods.
    3 marks
  6. Compare AUD 5,000 invested for 4 years at 4% simple interest and at 4% annual compound interest.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find the balance of AUD 3,400 after 5 years at 3.5% compounded annually.
    3 marks

    Use i=0.035 and n=5.

    3400⁢(1.035)5 = AUD 4,038.13.

    AUD 4,038.13
  2. AUD 900 grows to AUD 1,050. What interest has been earned?
    3 marks

    Interest = final balance − principal.

    1050−900=150.

    AUD 150.00
  3. An account reaches AUD 8,000 after 6 years at 5% compounded annually. Find its original principal.
    3 marks

    Rearrange P = B⁢/⁢(1+i)n.

    P = 8000⁢/⁢(1.05)6 = AUD 5,969.72.

    AUD 5,969.72
  4. AUD 2,000 earns a nominal annual rate of 6%, compounded monthly, for 2 years. Find the balance.
    3 marks

    The monthly rate is 0.06⁢/12=0.005 and there are 24 months.

    2000⁢(1.005)24 = AUD 2,254.32.

    AUD 2,254.32
  5. A model uses B=6000⁢(1.02)8. State the periodic rate and the number of periods.
    3 marks

    The multiplier 1.02 equals 1+i, so i=0.02.

    The exponent counts 8 periods. The formula alone does not identify whether the periods are months or years.

    2% per period; 8 periods.
  6. Compare AUD 5,000 invested for 4 years at 4% simple interest and at 4% annual compound interest.
    3 marks

    Simple balance = 5000⁢(1+0.04×4)=5800.

    Compound balance = 5000⁢(1.04)4 = AUD 5,849.29.

    Subtract the simple balance from the compound balance.

    Simple: AUD 5,800.00; compound: AUD 5,849.29; compound is AUD 49.29 higher.
Checking saved progress…

Continue learning

Effective interest rates

Next lesson
Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 General Mathematics financial models: investments and annuities, superannuation, income streams and borrowing. Original practice uses supplied hypothetical rates, taxes and fees; statutory or commercial conditions are not inferred.

Official curriculum source ↗
Back to Financial mathematics

Save your next step.

Create a free account to save your learning progress. Lessons and downloads stay free, with or without an account.

Create free account