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Year 10 · Pythagoras and Trigonometry · 18 min

Multi-step right-triangle problems

Break a length problem into right triangles, then combine the results to answer the actual question.

01 / LEARN

The idea, step by step

Choose one triangle at a time

Pythagoras links the three sides of one right-angled triangle. The hypotenuse is opposite the right angle, not automatically the side drawn at the top. Sketch the situation and mark a right angle before choosing a formula.

For two triangles, name the shared length. Find it from the triangle with enough information, then carry its unrounded value into the next calculation.

c2=a2+b2

Finish the whole problem

After finding a side, read the question again: you may still need a perimeter, a drop or the total amount of material. A diagonal, a vertical height and a total distance describe different quantities.

Retain exact roots until the last step. Include the unit and check that a hypotenuse exceeds either leg.

A common trap

Adding box dimensions to get its diagonal.

Instead: Adding edges measures a different route. Use perpendicular squared lengths for a diagonal.

02 / WORKED EXAMPLES

See the thinking

Example 1

Two linked triangles

A box is 12 cm long, 9 cm wide and 20 cm high. Find its space diagonal.

  1. The base diagonal is d=122+92=15 cm.
  2. The base diagonal and height form a second right triangle.
  3. The space diagonal is 152+202=25 cm.
25 cm
Example 2

Add the allowance

A cable joins the top of an 8 m pole to a ground point 6 m from its base. Allow 1 m extra for attaching it. How much cable is needed?

  1. The taut length is 82+62=10 m.
  2. The attachment allowance is additional cable, not a side of the triangle.
  3. Add 1 m to 10 m.
11 m

Check your understanding

A rectangle is 5 m by 12 m. Find its diagonal.

Show answer

13 m

d=52+122=13 m.

03 / WORKSHEET

Your turn

6 questions · 16 marks · Work at your own pace.

Read the questions online
  1. Find the diagonal of a 9 cm by 12 cm rectangle.
    2 marks
  2. A cuboid has perpendicular edges 3 m, 4 m and 12 m. Find its space diagonal.
    3 marks
  3. A 13 m ladder has its foot 5 m from a wall. How high does it reach?
    2 marks
  4. A rectangular garden has diagonal 26 m and width 10 m. Find its perimeter.
    3 marks
  5. A symmetrical roof has span 16 m and rise 6 m. Find the total length of its two sloping edges.
    3 marks
  6. A student claims a right triangle with hypotenuse 17 cm and leg 8 cm has other leg 19 cm. Correct the result and explain.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find the diagonal of a 9 cm by 12 cm rectangle.
    2 marks

    d2=92+122=225.

    d=15 cm.

    15 cm
  2. A cuboid has perpendicular edges 3 m, 4 m and 12 m. Find its space diagonal.
    3 marks

    The base diagonal is 32+42=5 m.

    The space diagonal is 52+122=13 m.

    13 m
  3. A 13 m ladder has its foot 5 m from a wall. How high does it reach?
    2 marks

    h2=132−52=144.

    h=12 m.

    12 m
  4. A rectangular garden has diagonal 26 m and width 10 m. Find its perimeter.
    3 marks

    The other side is 262−102=24 m.

    The perimeter is 2⁢(24+10)=68 m.

    68 m
  5. A symmetrical roof has span 16 m and rise 6 m. Find the total length of its two sloping edges.
    3 marks

    Each half has run 8 m.

    Each slope is 82+62=10 m.

    There are two slopes.

    20 m
  6. A student claims a right triangle with hypotenuse 17 cm and leg 8 cm has other leg 19 cm. Correct the result and explain.
    3 marks

    x2=172−82=225.

    x=15 cm.

    Subtract the known leg square from the hypotenuse square.

    15 cm; a leg cannot exceed the hypotenuse.
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Curriculum reference & lesson scope

Australian Curriculum v9 and South Australian school course scope

Right-triangle applications include AC9M10M03. The approved chapter also develops non-right-triangle methods, exact values and trigonometric functions within one normal Year 10 course.

Official curriculum source ↗
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