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Year 9 · Indices and scientific notation · 15 min

Measurement and time-scale applications

Use scientific notation with compatible measurement units and sensible interpretations of time and scale.

01 / LEARN

The idea, step by step

Numbers and units must travel together

1 kilometre is 103 metres, 1 millimetre is 10−3 metres and 1 micrometre is 10−6 metres. A scientific-notation coefficient does not tell you which unit was used.

Before dividing two lengths to find a scale factor, express them in the same unit. Dividing a distance by a speed gives a time only when the distance unit matches the speed unit. Show the conversion rather than silently changing it.

Interpret the result, not just the exponent

A value of 2.5×103 seconds is correct but may be easier to understand as 2500 seconds or about 41.7 minutes. Keep enough digits during a calculation, then round the final result to the precision requested.

Rate models often assume constant speed or identical repeated objects. State these assumptions and consider what was left out. For example, a download-time model may ignore connection delays, and a stack-thickness model may ignore air gaps.

A common trap

Dividing measurements written in different units without converting.

Instead: Convert both quantities to compatible units first, then carry out the scientific-notation calculation.

02 / WORKED EXAMPLES

See the thinking

Example 1

Compare a drawing with a real object

A cell is 8×10−6 m long. Its drawing is 4 cm long. Find the drawing magnification.

  1. Convert 4 cm to metres: 4×10−2 m.
  2. Magnification =4×10−28×10−6=0.5×104.
  3. Normalise to get 5×103=5000.
5000 times
Example 2

Find travel time

A signal travels 9×107 m at 3×108 m/s. How long does the journey take?

  1. t=dv; both distances use metres.
  2. t=9×1073×108=3×10−1 s.
  3. 3×10−1 s is 0.3 s.
0.3 s

Check your understanding

A sheet is 9×10−5 m thick. Find the thickness of 1000 sheets, ignoring gaps.

Show answer

0.09 m

(9×10−5)⁢(103)=9×10−2 m.

03 / WORKSHEET

Your turn

6 questions · 15 marks · Work at your own pace.

Read the questions online
  1. Write 3.5 km in metres using scientific notation.
    2 marks
  2. Write 0.0042 m in millimetres.
    2 marks
  3. A particle is 2.5×10−6 m wide. Express its width in micrometres.
    2 marks
  4. A beam travels 1.8×106 m in 6×10−3 s. Find its constant speed.
    3 marks
  5. A model is 15 cm long and represents a real object 30 m long. Find the scale factor from real object to model.
    3 marks
  6. A sensor records 2×104 readings each second. How many readings does it record in 5 minutes?
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Write 3.5 km in metres using scientific notation.
    2 marks

    1 km =103 m, so multiply 3.5 by 103.

    3.5×103 m
  2. Write 0.0042 m in millimetres.
    2 marks

    1 m =1000 mm.

    0.0042×1000=4.2.

    4.2 mm
  3. A particle is 2.5×10−6 m wide. Express its width in micrometres.
    2 marks

    1 micrometre =10−6 m.

    Divide 2.5×10−6 m by 10−6 m per micrometre.

    2.5 micrometres
  4. A beam travels 1.8×106 m in 6×10−3 s. Find its constant speed.
    3 marks

    v=d÷t=1.86×106−(−3)=0.3×109.

    Normalise to 3×108 m/s.

    3×108 m/s
  5. A model is 15 cm long and represents a real object 30 m long. Find the scale factor from real object to model.
    3 marks

    Convert 30 m to 3000 cm.

    15÷3000=1200.

    1200
  6. A sensor records 2×104 readings each second. How many readings does it record in 5 minutes?
    3 marks

    5 minutes =300=3×102 seconds.

    (2×104)⁢(3×102)=6×106.

    6×106 readings
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Curriculum reference & lesson scope

Australian Curriculum v9 / SA Curriculum

Year 9 numerical integer exponent laws and their extension to variables; scientific notation and practical measurement applications. Excludes fractional-index and full surd algebra taught in Year 10.

Official curriculum source ↗
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