The idea, step by step
Work backwards from a ratio
Two known sides give a side ratio. Inverse sine, cosine or tangent then gives the angle with that ratio. Write the fraction first, then apply the inverse function to the entire fraction.
On a calculator sin⁻¹, cos⁻¹ and tan⁻¹ mean inverse functions here, not reciprocals such as 1/sin.
The answer must fit the triangle
Use degrees and check for an answer between 0° and 90°. A sine or cosine input outside −1 to 1 is impossible; in this acute-angle setting it lies strictly between 0 and 1.
If opposite exceeds adjacent, the angle exceeds 45°. The other acute angle equals 90° minus the angle you found.
A common trap
Use 1/tan(0.75) to invert a tangent ratio.
Instead: Use the inverse-tangent command. A reciprocal calculates a different number.
See the thinking
Opposite and adjacent
Opposite = 9 cm and adjacent = 12 cm. Find θ.
- .
- .
Adjacent and hypotenuse
Adjacent = 7 m and hypotenuse = 10 m. Find θ.
- .
- .
Check your understanding
Opposite and adjacent are equal. Find θ.
Show answer
45°
, so .
Your turn
6 questions · 13 marks · Work at your own pace.
Read the questions online
- Find θ if o = 5 cm and h = 13 cm. Give two decimal places.2 marks
- Find θ if a = 12 cm and h = 13 cm. Give two decimal places.2 marks
- Find θ if o = 15 m and a = 8 m. Give two decimal places.2 marks
- An acute angle has sine 0.8. Find it to two decimal places.2 marks
- For hypotenuse 13 and opposite 5, a student enters sin⁻¹(13/5). Explain the error and correct it.3 marks
- One acute angle in a right triangle is 34.7°. Find the other.2 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Find θ if o = 5 cm and h = 13 cm. Give two decimal places.2 marks
.
22.62° - Find θ if a = 12 cm and h = 13 cm. Give two decimal places.2 marks
.
This agrees with the matching 5–12–13 triangle.
22.62° - Find θ if o = 15 m and a = 8 m. Give two decimal places.2 marks
.
Opposite exceeds adjacent, so θ exceeds 45°.
61.93° - An acute angle has sine 0.8. Find it to two decimal places.2 marks
.
53.13° - For hypotenuse 13 and opposite 5, a student enters sin⁻¹(13/5). Explain the error and correct it.3 marks
The side ratio was reversed.
13/5 exceeds 1 and cannot be a sine value.
Use - One acute angle in a right triangle is 34.7°. Find the other.2 marks
.
55.3°
Curriculum reference & lesson scope
Australian Curriculum v9 and SA Mathematics
Year 9 similarity, Pythagoras and right-triangle trigonometric ratios, with prerequisite revision. Non-right-triangle sine/cosine rules are not required.
Official curriculum source ↗