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Year 9 · Pythagoras and Trigonometry · 15 min

Finding an angle

Recover an acute angle from two sides using an inverse trigonometric function.

01 / LEARN

The idea, step by step

Work backwards from a ratio

Two known sides give a side ratio. Inverse sine, cosine or tangent then gives the angle with that ratio. Write the fraction first, then apply the inverse function to the entire fraction.

On a calculator sin⁻¹, cos⁻¹ and tan⁻¹ mean inverse functions here, not reciprocals such as 1/sin.

θ=tan−1(oa)

The answer must fit the triangle

Use degrees and check for an answer between 0° and 90°. A sine or cosine input outside −1 to 1 is impossible; in this acute-angle setting it lies strictly between 0 and 1.

If opposite exceeds adjacent, the angle exceeds 45°. The other acute angle equals 90° minus the angle you found.

A common trap

Use 1/tan(0.75) to invert a tangent ratio.

Instead: Use the inverse-tangent command. A reciprocal calculates a different number.

02 / WORKED EXAMPLES

See the thinking

Example 1

Opposite and adjacent

Opposite = 9 cm and adjacent = 12 cm. Find θ.

  1. tanθ=9⁢/12=0.75.
  2. θ=tan−1(0.75)≈36.8699⁢…∘.
36.87°
Example 2

Adjacent and hypotenuse

Adjacent = 7 m and hypotenuse = 10 m. Find θ.

  1. cosθ=7⁢/10.
  2. θ=cos−1(0.7)≈45.5730⁢…∘.
45.57°

Check your understanding

Opposite and adjacent are equal. Find θ.

Show answer

45°

tanθ=1, so θ=45∘.

03 / WORKSHEET

Your turn

6 questions · 13 marks · Work at your own pace.

Read the questions online
  1. Find θ if o = 5 cm and h = 13 cm. Give two decimal places.
    2 marks
  2. Find θ if a = 12 cm and h = 13 cm. Give two decimal places.
    2 marks
  3. Find θ if o = 15 m and a = 8 m. Give two decimal places.
    2 marks
  4. An acute angle has sine 0.8. Find it to two decimal places.
    2 marks
  5. For hypotenuse 13 and opposite 5, a student enters sin⁻¹(13/5). Explain the error and correct it.
    3 marks
  6. One acute angle in a right triangle is 34.7°. Find the other.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find θ if o = 5 cm and h = 13 cm. Give two decimal places.
    2 marks

    θ=sin−1(5⁢/13).

    22.62°
  2. Find θ if a = 12 cm and h = 13 cm. Give two decimal places.
    2 marks

    θ=cos−1(12⁢/13).

    This agrees with the matching 5–12–13 triangle.

    22.62°
  3. Find θ if o = 15 m and a = 8 m. Give two decimal places.
    2 marks

    θ=tan−1(15⁢/8).

    Opposite exceeds adjacent, so θ exceeds 45°.

    61.93°
  4. An acute angle has sine 0.8. Find it to two decimal places.
    2 marks

    θ=sin−1(0.8).

    53.13°
  5. For hypotenuse 13 and opposite 5, a student enters sin⁻¹(13/5). Explain the error and correct it.
    3 marks

    The side ratio was reversed.

    13/5 exceeds 1 and cannot be a sine value.

    Use sin−1(5⁢/13)
  6. One acute angle in a right triangle is 34.7°. Find the other.
    2 marks

    90∘−34.7∘=55.3∘.

    55.3°
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Mathematics

Year 9 similarity, Pythagoras and right-triangle trigonometric ratios, with prerequisite revision. Non-right-triangle sine/cosine rules are not required.

Official curriculum source ↗
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