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Year 11 · Counting and introductory statistics · 20 min

Multiplication principle

Count a sequence of choices by tracking how many choices are possible at each stage.

01 / LEARN

The idea, step by step

Count complete outcomes, not individual options

An outcome may contain several choices: a meal can have a main, a side and a drink. If every main can be paired with every side and every drink, multiply the numbers of options. The product counts complete meals, not the total number of menu entries. A tree or small table can make the combinations visible.

N=n1n2⋯nk

Update choices when a restriction changes the next stage

Independence of choices is not required for the multiplication principle. What matters is knowing how many continuations each partial choice has. For a code without repeated digits, the next stage has one fewer option. If different branches have different numbers of continuations, count the separate cases and add them; do not multiply one arbitrary branch size.

A common trap

Adding the numbers of options for stages of one outcome.

Instead: Multiply for successive choices; add only disjoint alternative cases.

02 / WORKED EXAMPLES

See the thinking

Example 1

A complete meal

A cafe offers 4 mains, 3 sides and 2 drinks. Every combination is available. How many meals are possible?

  1. Choose a main in 4 ways.
  2. For each main, choose a side in 3 ways and a drink in 2 ways.
  3. 4×3×2=24.
24 meals.
Example 2

A restricted number

How many three-digit numbers can be made from 0, 1, 2, 3, 4 without repetition?

  1. The first digit cannot be zero: 4 choices.
  2. After choosing it, 4 digits remain, then 3.
  3. 4×4×3=48.
48 numbers.

Check your understanding

There are 3 shirts and 4 trousers. How many outfits?

Show answer

12.

Each shirt can be paired with all 4 trousers: 3×4=12.

03 / WORKSHEET

Your turn

6 questions · 14 marks · Work at your own pace.

Read the questions online
  1. There are 5 sandwich fillings and 3 bread types. Count the sandwiches.
    2 marks
  2. A four-digit PIN may use digits 0–9 repeatedly. Count the PINs.
    2 marks
  3. A four-digit PIN has no repeated digits. Count it.
    2 marks
  4. Choose a captain and then a different vice-captain from 8 players. Count the choices.
    2 marks
  5. A password is either two letters A–D followed by a digit 0–9, or one letter A–D followed by two digits. Repetition is allowed. Count all passwords.
    3 marks
  6. A student claims three tasks with 4, 2 and 3 choices have 4+2+3=9 complete outcomes. Explain and correct the error.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. There are 5 sandwich fillings and 3 bread types. Count the sandwiches.
    2 marks

    5×3=15.

    15.
  2. A four-digit PIN may use digits 0–9 repeatedly. Count the PINs.
    2 marks

    A PIN may start with zero.

    104=10000.

    10,000.
  3. A four-digit PIN has no repeated digits. Count it.
    2 marks

    10×9×8×7=5040.

    5,040.
  4. Choose a captain and then a different vice-captain from 8 players. Count the choices.
    2 marks

    The roles differ.

    8×7=56.

    56.
  5. A password is either two letters A–D followed by a digit 0–9, or one letter A–D followed by two digits. Repetition is allowed. Count all passwords.
    3 marks

    The formats cannot overlap.

    42×10+4×102=160+400=560.

    560.
  6. A student claims three tasks with 4, 2 and 3 choices have 4+2+3=9 complete outcomes. Explain and correct the error.
    3 marks

    Adding counts options separately rather than complete triples.

    4×2×3=24.

    24 outcomes; each choice in one stage can combine with every choice in the next.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics: counting, binomial expansion, data, samples, summary measures and introductory normal distributions. These lessons provide the Counting and Statistics strand of the approved Methods preparation route.

Official curriculum source ↗
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