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Year 11 · Quadratics and polynomial graphs · 18 min

Completing the square

Rewrite quadratics around their turning points and solve using square form.

01 / LEARN

The idea, step by step

Create a perfect square

To complete x2+b⁢x, halve b and square the result. Add and subtract that square so the expression stays unchanged.

In (x−h)2+k, the square is nonnegative, so k is the minimum. A negative leading coefficient changes this to a maximum.

x2+b⁢x+c=(x+b2)2+c−b24

Keep the outside coefficient

When the leading coefficient is not 1, factor it out of the quadratic and linear terms first. Complete the square inside, then distribute the coefficient carefully.

When solving, isolate the square. A positive right side gives two branches, zero gives one and a negative right side gives no real solutions.

A common trap

Replacing x2+6⁢x with (x+3)2 alone.

Instead: The square adds 9: subtract 9 as well.

02 / WORKED EXAMPLES

See the thinking

Example 1

Reveal a minimum

Complete the square in x2−8⁢x+11.

  1. Half -8 is -4; its square is 16.
  2. Write x2−8⁢x+16−16+11.
  3. Combine constants.
(x−4)2−5
Example 2

Leading coefficient two

Rewrite 2x2+12⁢x+5 and find its minimum.

  1. Factor 2⁢(x2+6⁢x)+5.
  2. Inside, x2+6⁢x=(x+3)2−9.
  3. Hence 2⁢(x+3)2−18+5.
2⁢(x+3)2−13; minimum -13 at x=-3.

Check your understanding

Complete the square: x2+10⁢x+7.

Show answer

(x+5)2−18

Add/subtract 25, then combine 7-25.

03 / WORKSHEET

Your turn

6 questions · 14 marks · Work at your own pace.

Read the questions online
  1. Write x2+4⁢x+1 in completed-square form.
    2 marks
  2. Write x2−6⁢x+2 in completed-square form.
    2 marks
  3. Rewrite 3x2−12⁢x+8 in square form.
    3 marks
  4. Solve (x−2)2=7 exactly.
    2 marks
  5. Find the maximum of −2⁢(x+1)2+9.
    2 marks
  6. Solve x2−4⁢x−1=0 by completing the square.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Write x2+4⁢x+1 in completed-square form.
    2 marks

    Add/subtract 4.

    Group the perfect square.

    (x+2)2−3
  2. Write x2−6⁢x+2 in completed-square form.
    2 marks

    Add/subtract 9.

    Combine constants.

    (x−3)2−7
  3. Rewrite 3x2−12⁢x+8 in square form.
    3 marks

    Use 3⁢(x2−4⁢x)+8.

    Replace the inside with (x−2)2−4.

    3⁢(x−2)2−4
  4. Solve (x−2)2=7 exactly.
    2 marks

    Take both roots.

    Add 2.

    x=2±7
  5. Find the maximum of −2⁢(x+1)2+9.
    2 marks

    The square is at least zero.

    Its negative multiple is at most zero.

    9 at x=-1.
  6. Solve x2−4⁢x−1=0 by completing the square.
    3 marks

    Rewrite (x−2)2−5=0.

    Isolate the square and take both roots.

    x=2±5
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics topics 2.1–2.2: quadratic relationships, cubic and quartic polynomials. Original Ascent teaching sequence.

Official curriculum source ↗
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