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Year 12 · Integration · 16 min

Power/exponential/trigonometric antiderivatives

Integrate powers, natural exponentials and basic trigonometric functions, including linear changes of input.

01 / LEARN

The idea, step by step

Match the derivative pattern

The reverse rule must undo the complete derivative. Since the derivative of e3⁢x is 3e3⁢x, an antiderivative of e3⁢x needs a factor of 1⁢/3. The same adjustment works for sine and cosine of a linear expression.

For trigonometric integrals, angles are in radians. Also keep the sign: differentiating cosine gives negative sine, so integrating sine produces negative cosine.

∫ea⁢x+bd⁢x=1aea⁢x+b+C(a≠0)

Combine rules carefully

Write fractional powers before using the power rule: x=x1⁢/2 and 1⁢/x2=x−2. The power rule does not cover x−1; reciprocal linear terms are handled in the next lesson.

Linearity lets you integrate a sum of different function types. Check every coefficient by differentiating the complete result; the derivative check is especially useful for a negative linear input.

∫cos(a⁢x+b)d⁢x=sin(a⁢x+b)a+C;∫sin(a⁢x+b)d⁢x=−cos(a⁢x+b)a+C

A common trap

Increasing the power correctly but forgetting to divide by the new exponent or the linear-input coefficient.

Instead: Differentiate the proposed result. Any extra multiplier shows exactly which factor still needs to be divided out.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example

Find ∫(5x4−3ex+2cosx)d⁢x.

  1. Use the power rule on the first term.
  2. The natural exponential is unchanged on integration.
  3. The antiderivative of cosine is sine; retain coefficient 2.
x5−3ex+2sinx+C
Example 2

Worked example

Find ∫cos(3⁢x)d⁢x.

  1. The derivative of sin(3⁢x) is 3cos(3⁢x).
  2. Divide by 3 to undo that factor.
  3. Differentiate the answer to recover the integrand.
sin(3⁢x)⁢/3+C

Check your understanding

Find ∫2e2⁢xd⁢x.

Show answer

e2⁢x+C

The derivative of the answer is 2e2⁢x.

03 / WORKSHEET

Your turn

6 questions · 18 marks · Work at your own pace.

Read the questions online
  1. Find ∫(8x3+ex)d⁢x.
    3 marks
  2. Find ∫xd⁢x for x>0.
    3 marks
  3. Find ∫x−2d⁢x on x>0.
    3 marks
  4. Find ∫4e−2⁢xd⁢x.
    3 marks
  5. Find ∫3sin(2⁢x)d⁢x.
    3 marks
  6. Find ∫(2cosx−sinx)d⁢x.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find ∫(8x3+ex)d⁢x.
    3 marks

    Apply the power and natural-exponential rules.

    2x4+ex+C
  2. Find ∫xd⁢x for x>0.
    3 marks

    Rewrite as x1⁢/2, then divide x3⁢/2 by 3⁢/2.

    23x3⁢/2+C
  3. Find ∫x−2d⁢x on x>0.
    3 marks

    Raise the power to −1 and divide by −1.

    −x−1+C
  4. Find ∫4e−2⁢xd⁢x.
    3 marks

    Divide coefficient 4 by −2.

    −2e−2⁢x+C
  5. Find ∫3sin(2⁢x)d⁢x.
    3 marks

    Use the negative-cosine antiderivative and divide by 2.

    −32cos(2⁢x)+C
  6. Find ∫(2cosx−sinx)d⁢x.
    3 marks

    Integrate the two terms separately; check both signs.

    2sinx+cosx+C
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Antiderivatives involving reciprocal linear expressions, linked back to logarithmic derivatives

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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Mathematical Methods integration and logarithmic antiderivatives; original learning and assessment material, with by-hand methods and explicitly described numerical models.

Official curriculum source ↗
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