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Year 6 · Number properties and calculations · 10 min

Efficient calculation and estimation

Choose efficient whole-number strategies and use estimates to check the result.

01 / LEARN

The idea, step by step

Change the calculation without changing its value

Near-round numbers make some calculations shorter. For 398+247, use 400+247 and remove the extra 2. For 25×16, group the factors as 25×4×4 to create 100.

Explain why a compensation or regrouping works. A short method is useful only if it preserves the value of the original calculation.

Estimate before trusting an answer

Round to convenient values and calculate a rough result. An estimate is not an exact answer, but it can reveal a misplaced digit or a wrong operation.

The context tells you what an answer must mean. A bus-seat problem needs a whole number of buses. An estimate checks the size, while the final calculation decides whether an extra bus is needed.

A common trap

49×8 is exactly 400 because 49 rounds to 50.

Instead: 400 is an estimate. Subtract the extra group of 8 to get the exact answer 392.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example 1

Calculate 599+286 efficiently.

  1. Use 600+286=886.
  2. One extra was added, so subtract 1.
885.
Example 2

Worked example 2

A school buys 18 boxes of 24 pencils. Find the total and check it.

  1. 20×24=480; remove 2×24=48.
  2. 480−48=432. The estimate 20×20=400 is of a similar size.
432 pencils.

Check your understanding

Choose a sensible estimate for 198×31: 600, 6,000 or 60,000.

Show answer

6,000.

200×30=6,000 is close to the original calculation.

03 / WORKSHEET

Your turn

6 questions · 12 marks · Work at your own pace.

Read the questions online
  1. Use compensation to calculate 497+358.
    2 marks
  2. Calculate 25×28 by making a factor of 100.
    2 marks
  3. Calculate 1,002−498 efficiently.
    2 marks
  4. Estimate 61×39 using convenient tens.
    1 mark
  5. A calculator shows 7,200 for 48×15. Explain why this is unreasonable, then correct it.
    3 marks
  6. A club has 178 people. Each bus seats 40. How many buses are needed?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Use compensation to calculate 497+358.
    2 marks

    500+358−3=855.

    855.
  2. Calculate 25×28 by making a factor of 100.
    2 marks

    25×4×7=100×7=700.

    700.
  3. Calculate 1,002−498 efficiently.
    2 marks

    1,002−500+2=504.

    504.
  4. Estimate 61×39 using convenient tens.
    1 mark

    60×40=2,400.

    About 2,400.
  5. A calculator shows 7,200 for 48×15. Explain why this is unreasonable, then correct it.
    3 marks

    50×15 is about 750. Exactly, 48×10+48×5=480+240=720.

    It is about ten times too large; the correct answer is 720.
  6. A club has 178 people. Each bus seats 40. How many buses are needed?
    2 marks

    Four seat 160, leaving 18 people, so one more is needed.

    5 buses.
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Curriculum reference & lesson scope

Australian Curriculum v9 and SA Curriculum Mathematics

Prime/composite/square numbers; factors/multiples revision; efficient calculation and estimation.

Official curriculum source ↗
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