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Year 11 · Matrices and transformations · 20 min

Translations as vectors

Describe a translation by a displacement vector and explain why a 2 by 2 matrix alone cannot produce a non-zero translation.

01 / LEARN

The idea, step by step

Add the same displacement

A translation moves every point through the same displacement. If its vector is t, a position vector p becomes p+t. Distances, angles and orientation are preserved because differences between position vectors do not change.

Read the components as horizontal and vertical changes. The displacement does not depend on the starting point.

Linear transformations fix the origin

Every ordinary matrix product sends the zero vector to zero: A0=0. A non-zero translation moves the origin, so it cannot be represented by a 2 by 2 matrix acting alone on two-dimensional position vectors.

An affine rule p↦A⁢p+t combines a matrix transformation with a translation. Its inverse first subtracts t, then applies the inverse matrix, when it exists.

A common trap

Using a diagonal matrix to represent a translation.

Instead: A diagonal matrix scales coordinates; a translation adds a fixed vector.

02 / WORKED EXAMPLES

See the thinking

Example 1

Translate a triangle

Translate P=(1,2), Q=(3,2), R=(2,5) by t=(−2,1).

  1. Add -2 to each x-coordinate and 1 to each y-coordinate.
  2. For example P maps to (1-2,2+1)=(-1,3).
P′=(−1,3), Q′=(1,3), R′=(0,6).
Example 2

Undo an affine rule

The rule sends (x,y) to (2⁢x+3,2⁢y−1). Find the input whose image is (11,5).

  1. Subtract the translation (3,-1), giving (8,6).
  2. Divide both coordinates by 2.
Input (4,3).

Check your understanding

What translation sends (2,−1) to (−3,4)?

Show answer

(−5,5).

Subtract start from finish.

03 / WORKSHEET

Your turn

6 questions · 12 marks · Work at your own pace.

Read the questions online
  1. Translate (4,−2) by (3,5).
    2 marks
  2. Find the displacement from (−1,6) to (3,2).
    2 marks
  3. Translate by (−4,2), then by (1,−5). State the single equivalent translation.
    2 marks
  4. Explain why no 2 by 2 matrix alone sends every point two units right.
    2 marks
  5. Find p if 3⁢p+(2,−1)=(8,5).
    2 marks
  6. Under a translation, P=(1,4) becomes (6,2). Find the image of Q=(−2,0).
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Translate (4,−2) by (3,5).
    2 marks

    Add the corresponding components.

    (7,3).
  2. Find the displacement from (−1,6) to (3,2).
    2 marks

    Subtract start from finish.

    (4,−4).
  3. Translate by (−4,2), then by (1,−5). State the single equivalent translation.
    2 marks

    Add the displacement vectors.

    (−3,−3).
  4. Explain why no 2 by 2 matrix alone sends every point two units right.
    2 marks

    The origin would need to move to (2,0), contradicting A0=0.

    Every matrix fixes the origin.
  5. Find p if 3⁢p+(2,−1)=(8,5).
    2 marks

    Subtract (2,-1) to obtain (6,6).

    Divide by 3.

    p=(2,2).
  6. Under a translation, P=(1,4) becomes (6,2). Find the image of Q=(−2,0).
    2 marks

    The translation vector is (5,-2).

    Add this to Q.

    (3,−2).
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics: matrices and transformations; original lessons follow the approved school-sized chapter structure.

Official curriculum source ↗
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