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Year 11 · Sequences and series · 20 min

Geometric sequences

Recognise constant ratios and handle fractional ratios, alternating signs and index conventions.

01 / LEARN

The idea, step by step

Constant multiplication

A geometric sequence multiplies each term by a fixed ratio r. For nonzero consecutive terms, divide the later term by the earlier term. With first term u1=a, the first exponent is zero.

A negative ratio alternates the signs. Positive ratios smaller than 1 produce decay when the first term is positive. A decreasing list need not be geometric.

un=arn−1

More than one possible ratio

Non-adjacent terms give a power of r. An even power may permit two real ratios, one positive and one negative. Retain both unless the context or another supplied term rules one out.

A threshold calculation may use logarithms, but the answer must still be an allowed integer index. Check the adjacent terms around the threshold.

A common trap

With first index 1 the formula is arn.

Instead: Use arn−1; an index-zero model instead uses u0rn.

02 / WORKED EXAMPLES

See the thinking

Example 1

Alternating geometric terms

For 6,−18,54,…, find u7.

  1. r=−3.
  2. u7=6⁢(−3)6=4374.
4374.
Example 2

Two possible ratios

u1=3,u3=12 in a real geometric sequence. Find all possible second terms.

  1. 3r2=12 gives r=±2.
  2. Then u2=3⁢r=±6.
u2=6 or −6.

Check your understanding

For a=80,r=1⁢/2, find u5.

Show answer

5.

80⁢(1⁢/2)4=5.

03 / WORKSHEET

Your turn

6 questions · 13 marks · Work at your own pace.

Read the questions online
  1. Find r,u6 for 4,12,36,….
    2 marks
  2. Find u8 if a=128,r=−1⁢/2.
    2 marks
  3. A positive geometric sequence has u2=10,u5=80. Find a,r.
    2 marks
  4. Is 2,6,18,55 geometric?
    2 marks
  5. Find both real geometric sequences with u1=8,u3=2. Give the first four terms.
    2 marks
  6. A culture has 300 cells at hour zero and doubles hourly. Give its rule and first whole hour above 10,000.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find r,u6 for 4,12,36,….
    2 marks

    4⁢(35)=972.

    r=3,u6=972.
  2. Find u8 if a=128,r=−1⁢/2.
    2 marks

    128⁢(−1⁢/2)7=−1.

    −1.
  3. A positive geometric sequence has u2=10,u5=80. Find a,r.
    2 marks

    r3=80⁢/10=8 and a=10⁢/2=5.

    a=5,r=2.
  4. Is 2,6,18,55 geometric?
    2 marks

    The first two ratios are 3, but 55⁢/18≠3.

    No.
  5. Find both real geometric sequences with u1=8,u3=2. Give the first four terms.
    2 marks

    r2=1⁢/4, so r=±1⁢/2.

    8,4,2,1 and 8,−4,2,−1.
  6. A culture has 300 cells at hour zero and doubles hourly. Give its rule and first whole hour above 10,000.
    3 marks

    N5=9600 and N6=19200.

    Nn=300⁢(2n); hour 6.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics sequence and series content with introductory induction, regrouped into an original school-sized chapter.

Official curriculum source ↗
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