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Year 11 · Sequences and series · 20 min

Infinite geometric sums and convergence

Decide whether an infinite geometric sum exists and interpret its limiting value and remaining tail.

01 / LEARN

The idea, step by step

A sum approached by finite sums

If ∣⁢r⁢∣<1, the powers rn approach zero. The finite-sum formula then approaches a⁢/⁢(1−r). With a nonzero first term, ratios of magnitude at least 1 do not produce a convergent geometric series.

The terms tending to zero are necessary for any convergent series, but this is not a general sufficient test. The result here is justified specifically for geometric series.

S∞=a1−rwhen ⁢∣⁢r⁢∣<1

There is no final term

The symbol S∞ is the limit of partial sums, not a sum ending at a last index. The tail after n terms is itself geometric, beginning with arn and having sum arn/⁢(1−r).

An ideal bouncing model may contain infinitely many shorter journeys while a real ball eventually stops. State the model assumptions before interpreting a limiting total.

A common trap

Numerically decreasing terms always give convergence.

Instead: For example −2,−4,−8,… decreases but diverges. The ratio magnitude must be below 1.

02 / WORKED EXAMPLES

See the thinking

Example 1

An alternating infinite sum

Find 9−3+1−1⁢/3+⋯.

  1. r=−1⁢/3 has magnitude below 1.
  2. S∞=9⁢/⁢(1+1⁢/3)=27⁢/4.
27⁢/4.
Example 2

Controlling a remaining tail

For 1+1⁢/2+1⁢/4+⋯, find how many terms give a remaining tail below 0.01.

  1. The tail is 21−n.
  2. At n=7 it is 1⁢/64>0.01; at n=8 it is 1⁢/128<0.01.
At least 8 terms.

Check your understanding

Does 4+6+9+⋯ converge?

Show answer

No.

r=3⁢/2; the terms do not approach zero.

03 / WORKSHEET

Your turn

6 questions · 13 marks · Work at your own pace.

Read the questions online
  1. Find 12+3+3⁢/4+⋯ to infinity.
    2 marks
  2. Find the infinite sum for a=5,r=−0.6.
    2 marks
  3. A geometric series starts at 8 and sums to 20. Find its ratio.
    2 marks
  4. Use partial sums to explain why 1−1+1−1+⋯ does not converge.
    2 marks
  5. A ball falls 2 m and rebounds to half its preceding height each time. Find the ideal total vertical distance.
    3 marks
  6. For 10+5+2.5+⋯, find the tail after four terms.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find 12+3+3⁢/4+⋯ to infinity.
    2 marks

    12⁢/⁢(1−1⁢/4)=16.

    16.
  2. Find the infinite sum for a=5,r=−0.6.
    2 marks

    5⁢/⁢(1+0.6)=3.125.

    25⁢/8=3.125.
  3. A geometric series starts at 8 and sums to 20. Find its ratio.
    2 marks

    8⁢/⁢(1−r)=20 gives r=3⁢/5.

    3⁢/5.
  4. Use partial sums to explain why 1−1+1−1+⋯ does not converge.
    2 marks

    They do not approach one value.

    Partial sums alternate between 1 and 0.
  5. A ball falls 2 m and rebounds to half its preceding height each time. Find the ideal total vertical distance.
    3 marks

    The first fall is 2 m; later paired journeys total 2⁢(1+1⁢/2+⋯)=4 m.

    6 m.
  6. For 10+5+2.5+⋯, find the tail after four terms.
    2 marks

    The fifth term is 10⁢(1⁢/2)4=5⁢/8; its tail sums to (5⁢/8)⁢/⁢(1⁢/2)=5⁢/4.

    1.25.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics sequence and series content with introductory induction, regrouped into an original school-sized chapter.

Official curriculum source ↗
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