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Year 12 · Complex Numbers · 22 min

Multiplication as rotation/dilation

Interpret multiplication as a combined turn and change of scale.

01 / LEARN

The idea, step by step

The geometry of a fixed multiplier

For w=a⁢z with a=ρ⁢cis⁢ϕ≠0, every nonzero point has its distance from the origin multiplied by ρ and its direction increased by ϕ. This is a dilation of scale factor ρ and an anticlockwise rotation through ϕ about the origin.

The multiplier i rotates by π⁢/2, −1 rotates by π, and a positive real multiplier only changes scale. The origin remains fixed. Multiplication by zero collapses the whole plane to zero and is not an invertible rotation-dilation.

Translation and inverse transformations

A map w=a⁢z+b first multiplies by a and then translates by b. Its inverse is z=(w−b)⁢/⁢a when a≠0. Keep the order: translating first would generally give a different result.

If a known nonzero point z maps to w under a pure multiplication, then a=w⁢/⁢z. For two successive multipliers, multiply them: scales multiply and angles add.

A common trap

Multiplication by −2 is a reflection in the real axis.

Instead: It is a scale factor 2 followed by a half-turn. Reflection in the real axis is conjugation, z↦z¯.

02 / WORKED EXAMPLES

See the thinking

Example 1

A quarter-turn

Under w=i⁢z, find the image of z=2+i and describe the transformation.

  1. i⁢(2+i)=2⁢i+i2=−1+2⁢i.
  2. ∣⁢i⁢∣=1, so no change of scale occurs.
w=−1+2⁢i; anticlockwise rotation through π⁢/2 about the origin.
Example 2

Recover the multiplier

A pure multiplication maps 1−i to 4. Find the multiplier and describe it.

  1. a=4⁢/⁢(1−i)=4⁢(1+i)⁢/2=2+2⁢i.
  2. Its modulus is 8=22 and its argument is π⁢/4.
a=2+2⁢i=22cis⁢(π⁢/4); scale by 22, rotate anticlockwise by π⁢/4.

Check your understanding

Describe multiplication by 2⁢cis⁢(−π⁢/3).

Show answer

Scale by 2 and rotate clockwise by π⁢/3 about the origin.

A negative change in argument is clockwise.

03 / WORKSHEET

Your turn

6 questions · 14 marks · Work at your own pace.

Read the questions online
  1. Find the image of 3−2⁢i under multiplication by i.
    2 marks
  2. Describe the map w=−3⁢z.
    2 marks
  3. A robot step is represented by z=2+i. A turn-and-scale instruction multiplies it by 1+i. Find the new step.
    3 marks
  4. Find the multiplier taking 2 to −2+23i.
    2 marks
  5. Find the inverse of w=2⁢i⁢z+3.
    3 marks
  6. Two instructions multiply successively by 2⁢i and −i⁢/2. What is the combined transformation?
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find the image of 3−2⁢i under multiplication by i.
    2 marks

    i⁢(3−2⁢i)=3⁢i−2i2=2+3⁢i.

    2+3⁢i.
  2. Describe the map w=−3⁢z.
    2 marks

    −3=3⁢cis⁢π.

    Dilation of scale factor 3 and rotation through π about the origin.
  3. A robot step is represented by z=2+i. A turn-and-scale instruction multiplies it by 1+i. Find the new step.
    3 marks

    (1+i)⁢(2+i)=2+3⁢i+i2=1+3⁢i. The instruction scales by 2 and rotates by π⁢/4.

    1+3⁢i.
  4. Find the multiplier taking 2 to −2+23i.
    2 marks

    Divide image by original: a=(−2+23i)⁢/2. Its modulus is 2 and quadrant-II angle is 2⁢π⁢/3.

    −1+3i=2⁢cis⁢(2⁢π⁢/3).
  5. Find the inverse of w=2⁢i⁢z+3.
    3 marks

    Subtract 3 first, then divide by 2⁢i.

    z=(w−3)⁢/⁢(2⁢i)=−i2⁢(w−3).
  6. Two instructions multiply successively by 2⁢i and −i⁢/2. What is the combined transformation?
    2 marks

    The combined multiplier is (2⁢i)⁢(−i⁢/2)=−i2=1.

    The identity transformation.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Specialist Mathematics complex numbers: Cartesian and polar representations, de Moivre, roots and roots of unity, Argand geometry and loci, complex factorisation and conjugate roots of real polynomials. Real-polynomial techniques are taught in the separate Real Polynomials chapter.

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