The idea, step by step
Interpret the integrand and the differential
An integral combines a rate with a change in its input variable. A flow in litres per minute integrated over minutes gives litres. A cross-sectional area in square metres integrated along metres gives cubic metres. Units help check whether the chosen model matches the question.
An accumulated change is not automatically a final amount. Add the initial amount when the question asks for the final quantity. State the interval and the model assumptions; predictions outside the model's sensible range need caution.
Check the result in context
The average value of f over [a,b] is . It has the same units as f, unlike the raw integral. Average speed and average signed velocity are different when motion reverses.
Use the graph, a rough bound and an independent derivative check to judge plausibility. Report whether an exact or rounded result is useful, including units and the meaning of the answer rather than only a number.
A common trap
Integrating a rate always gives the final amount.
Instead: It gives the change over the interval. Include the starting amount when a final amount is requested.
See the thinking
Worked example 1
A pipe has cross-sectional area A(x)=4x+1 square metres for 0<=x<=3 metres. Find its volume.
- Volume is the integral of A along the pipe.
- .
Worked example 2
A force F(x)=3x squared+2 N acts along a straight displacement from x=0 to 2 m. Find the work.
- Work is .
- Evaluate .
Check your understanding
A rate in metres per second is integrated over seconds. What are the resulting units?
Show answer
Metres.
The time units cancel, leaving displacement units.
Your turn
6 questions · 12 marks · Work at your own pace.
Read the questions online
- Water enters at 2t+3 litres/minute for 0<=t<=4. Initially there are 10 litres. Find the final amount.2 marks
- Find the average temperature 20+2t degrees C over 0<=t<=4 hours.2 marks
- Velocity is v=t-2 m/s for 0<=t<=4. Find displacement and total distance.2 marks
- A population increases at 100 exp(0.1t) people/year for 0<=t<=10. Find the increase.2 marks
- Marginal cost is 6q+10 dollars/unit. Find the cost increase when output rises from q=0 to 5.2 marks
- A solid has cross-section area pi(1+x) squared for 0<=x<=2 metres. Find its volume.2 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Water enters at 2t+3 litres/minute for 0<=t<=4. Initially there are 10 litres. Find the final amount.2 marks
The added amount is .
Add the initial 10 litres.
litres - Find the average temperature 20+2t degrees C over 0<=t<=4 hours.2 marks
Integrate to obtain 96 degree-hours.
Divide by the 4-hour interval.
. - Velocity is v=t-2 m/s for 0<=t<=4. Find displacement and total distance.2 marks
The signed integral cancels.
Split at t=2 and integrate speed on each side.
Displacement 0 m; distance 4 m. - A population increases at 100 exp(0.1t) people/year for 0<=t<=10. Find the increase.2 marks
An antiderivative is 1000 exp(0.1t).
Subtract its t=0 value from its t=10 value.
people, approximately 1718. - Marginal cost is 6q+10 dollars/unit. Find the cost increase when output rises from q=0 to 5.2 marks
Integrate marginal cost over output.
.
. - A solid has cross-section area pi(1+x) squared for 0<=x<=2 metres. Find its volume.2 marks
Integrate pi times .
Evaluate to pi times .
.
Curriculum reference & lesson scope
SACE Board of South Australia
Stage 2 Specialist Mathematics integration techniques and applications, including inverse-trigonometric patterns, substitution, parts, simple partial fractions, areas and solids of revolution.
Official curriculum source ↗