The idea, step by step
Work component by component
The derivative of is . Apply ordinary scalar rules, including chain-rule factors, to each corresponding component.
Integrating introduces a vector constant . Each component has an independent constant; one scalar constant cannot generally serve all coordinates.
Check a recovered position
Integrate velocity to obtain a position family, then substitute the initial time to determine each constant. Differentiate the result and check the initial vector separately.
Definite vector integration gives displacement: . It does not give total distance along a curved path.
A common trap
The integration constant is identical in all coordinates.
Instead: Each coordinate has its own constant.
See the thinking
Worked example
Differentiate .
- Use the power rule on the first coordinate.
- The exponential and sine coordinates need chain factors 2 and 3.
- Retain component order.
Worked example
Given and , find position.
- Integrate to .
- At zero the constants form (1, -2, 5).
- Differentiate to check the velocity.
Check your understanding
Differentiate .
Show answer
Apply the chain rule to the cosine coordinate.
Your turn
6 questions · 12 marks · Work at your own pace.
Read the questions online
- Differentiate for t>0.2 marks
- Find the second derivative of .2 marks
- Integrate with initial position (0, 1, -1) at zero.2 marks
- Evaluate .2 marks
- Given and , find position.2 marks
- Evaluate .2 marks
Read the worked solutions
Equivalent correct methods earn the corresponding marks. Include units where asked.
- Differentiate for t>0.2 marks
Use the power rule.
The logarithmic coordinate requires a positive domain.
- Find the second derivative of .2 marks
The first derivative is .
Differentiate again.
- Integrate with initial position (0, 1, -1) at zero.2 marks
Integrate each coordinate.
Use one constant for each initial coordinate.
- Evaluate .2 marks
Antiderivative .
Evaluate upper minus lower.
- Given and , find position.2 marks
Integrate to .
Initial values give .
- Evaluate .2 marks
Use antiderivative .
Subtract values at both endpoints.
Curriculum reference & lesson scope
SACE Board of South Australia
Stage 2 Specialist Mathematics topic 6.3–6.5: polynomial and trigonometric parameterisations, related coordinate rates, motion, tangent directions and arc length. This is school Vector calculus, not vector-field calculus.
Official curriculum source ↗