ASCENTLEARNING
Join a weekly class
Skip to learning content
Year 10 · Algebra · 15 min

Expanding products

Use the distributive law to expand products accurately, including negative signs and variable factors.

01 / LEARN

The idea, step by step

Distribute to every term

In a⁢(b+c), the outside factor multiplies both terms: a⁢b+a⁢c. The same rule works with subtraction, negative coefficients and variable factors. Writing the two products before simplifying makes sign errors easier to catch.

a⁢(b+c)=a⁢b+a⁢c

More than one bracket

For two factors containing sums, multiply each term in the first bracket by each term in the second. Organise the products in a short list or grid, then collect like terms. Quadratic products and their factorisation are explored further in Quadratics and Parabolas; the distributive law is the common principle.

A common trap

−3⁢(x−4)=−3⁢x−12.

Instead: The second product is (−3)⁢(−4)=+12, so the result is −3⁢x+12.

02 / WORKED EXAMPLES

See the thinking

Example 1

A variable multiplier

Expand 3⁢x⁢(2⁢x−5).

  1. Multiply 3⁢x by 2⁢x to obtain 6x2.
  2. Multiply 3⁢x by −5 to obtain −15⁢x.
6x2−15⁢x
Example 2

A negative multiplier

Expand and simplify −2⁢(3⁢a−4⁢b)+5⁢a.

  1. Distribute −2: −6⁢a+8⁢b+5⁢a.
  2. Collect −6⁢a+5⁢a=−a.
−a+8⁢b

Check your understanding

Expand −4⁢p⁢(2⁢p−3).

Show answer

−8p2+12⁢p

Both bracket terms are multiplied by −4⁢p; the negative times negative gives +12⁢p.

03 / WORKSHEET

Your turn

6 questions · 14 marks · Work at your own pace.

Read the questions online
  1. Expand 5⁢(x+3).
    2 marks
  2. Expand −3⁢(2⁢a−7).
    2 marks
  3. Expand 2⁢x⁢(4⁢x+5).
    2 marks
  4. Expand and simplify 4⁢(2⁢y−1)−3⁢(y+2).
    2 marks
  5. A shop packs n identical trays. Each tray has 3⁢a+2 items. Another 4⁢n loose items are added. Expand and simplify the total.
    3 marks
  6. Expand (2⁢a+b)⁢(c−3) without collecting unlike terms.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Expand 5⁢(x+3).
    2 marks

    Multiply both terms by 5.

    5⁢x+15
  2. Expand −3⁢(2⁢a−7).
    2 marks

    Compute (−3)⁢(2⁢a) and (−3)⁢(−7).

    −6⁢a+21
  3. Expand 2⁢x⁢(4⁢x+5).
    2 marks

    Multiply the coefficients and variable factors.

    8x2+10⁢x
  4. Expand and simplify 4⁢(2⁢y−1)−3⁢(y+2).
    2 marks

    8⁢y−4−3⁢y−6.

    Collect the terms.

    5⁢y−10
  5. A shop packs n identical trays. Each tray has 3⁢a+2 items. Another 4⁢n loose items are added. Expand and simplify the total.
    3 marks

    n⁢(3⁢a+2)+4⁢n=3⁢a⁢n+2⁢n+4⁢n.

    Combine the n terms.

    3⁢a⁢n+6⁢n
  6. Expand (2⁢a+b)⁢(c−3) without collecting unlike terms.
    3 marks

    The four products are 2⁢a⁢c,−6⁢a,b⁢c,−3⁢b.

    2⁢a⁢c−6⁢a+b⁢c−3⁢b
Checking saved progress…

Continue learning

Common-factor factorisation

Next lesson
Curriculum reference & lesson scope

Australian Curriculum v9 and South Australian Mathematics Curriculum

Year 10 algebra, including the approved fuller school-course treatment of rational expressions and formula restrictions; quadratic methods are in their own chapter.

Official curriculum source ↗
Back to Algebra

Save your next step.

Create a free account to save your learning progress. Lessons and downloads stay free, with or without an account.

Create free account