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Year 9 · Indices and scientific notation · 15 min

Comparing/calculating very large and small quantities

Compare scientific quantities and calculate with them, normalising the final coefficient.

01 / LEARN

The idea, step by step

Compare the scale first

For positive values in standard scientific notation, compare the exponents first. If they match, compare the coefficients. For example, 8.7×104<1.2×105, even though 8.7 is greater than 1.2.

To multiply, multiply coefficients and add exponents. To divide, divide coefficients and subtract exponents. Rewrite the result if its coefficient is outside 1≤a<10.

Addition needs a shared unit of scale

Powers of ten act like units. Before adding 4.2×105 and 7×104, rewrite the second as 0.7×105. Then the coefficients can be added to give 4.9×105.

Unlike multiplication, addition does not use the sum of exponents. Keep track of the question units and use an estimate to check the final scale. A ratio of two quantities in the same units is dimensionless.

A common trap

Adding exponents when adding two numbers in scientific notation.

Instead: Align the powers before adding coefficients. Adding exponents is a multiplication law.

02 / WORKED EXAMPLES

See the thinking

Example 1

Multiply and normalise

Calculate (6×104)⁢(5×10−2).

  1. Multiply coefficients: 6×5=30.
  2. Add exponents: 4+(−2)=2, giving 30×102.
  3. Normalise: 30×102=3×103.
3×103
Example 2

Subtract matching scales

Calculate 8.1×106−6×105.

  1. Rewrite 6×105=0.6×106.
  2. Subtract coefficients: 8.1−0.6=7.5.
  3. The result is 7.5×106.
7.5×106

Check your understanding

Which is larger: 9.1×10−4 or 2.3×10−3?

Show answer

2.3×10−3

The second equals 23×10−4, which is larger than 9.1×10−4.

03 / WORKSHEET

Your turn

6 questions · 13 marks · Work at your own pace.

Read the questions online
  1. Order from smallest to largest: 3.2×105, 7.4×104, 2.9×105.
    2 marks
  2. Calculate (4×103)⁢(2×105).
    2 marks
  3. Calculate 9×1073×102.
    2 marks
  4. Calculate 2.4×106+5×105.
    2 marks
  5. Calculate (8×10−3)⁢(5×10−4).
    2 marks
  6. A file of 6×108 bytes is sent at 2×106 bytes per second. Find the time, assuming a constant rate.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Order from smallest to largest: 3.2×105, 7.4×104, 2.9×105.
    2 marks

    The 104 quantity is smaller than both 105 quantities.

    For matching powers compare 2.9 with 3.2.

    7.4×104,2.9×105,3.2×105
  2. Calculate (4×103)⁢(2×105).
    2 marks

    4×2=8 and 3+5=8.

    8×108
  3. Calculate 9×1073×102.
    2 marks

    9÷3=3 and 7−2=5.

    3×105
  4. Calculate 2.4×106+5×105.
    2 marks

    5×105=0.5×106.

    (2.4+0.5)×106=2.9×106.

    2.9×106
  5. Calculate (8×10−3)⁢(5×10−4).
    2 marks

    8×5=40 and −3+(−4)=−7.

    40×10−7=4×10−6.

    4×10−6
  6. A file of 6×108 bytes is sent at 2×106 bytes per second. Find the time, assuming a constant rate.
    3 marks

    t=6×1082×106=3×102.

    3×102=300 seconds.

    300 seconds
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Curriculum reference & lesson scope

Australian Curriculum v9 / SA Curriculum

Year 9 numerical integer exponent laws and their extension to variables; scientific notation and practical measurement applications. Excludes fractional-index and full surd algebra taught in Year 10.

Official curriculum source ↗
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