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Year 12 · Integration techniques and applications · 22 min

Integration by parts

Use integration by parts for products and repeat it when needed.

01 / LEARN

The idea, step by step

Reverse the product rule

Integrating the product-rule identity gives ∫ud⁢v=u⁢v−∫vd⁢u. Choose u so its derivative simplifies, and choose dv so it has a manageable antiderivative. Keep the minus sign attached to the whole remaining integral.

Polynomials paired with exponentials or trigonometric functions often simplify when the polynomial is differentiated. For logarithms or inverse trigonometric functions alone, use an implicit factor 1 as dv.

Repeat and verify

A quadratic polynomial times an exponential usually requires two applications. Each stage should reduce the polynomial degree. Some cyclic products return the original integral; collect it algebraically rather than continuing forever.

For definite integrals, apply bounds to both the uv term and the remaining integral, or find a full antiderivative first. Differentiate your final result to check product signs and inner-frequency factors.

A common trap

The product antiderivative is the product of the two antiderivatives.

Instead: Use the product-rule identity; simple multiplication generally differentiates to extra terms.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example 1

Find ∫xexd⁢x.

  1. Choose u=x and dv=exp(x)dx.
  2. Then the result is x exp(x) minus exp(x).
(x−1)ex+C.
Example 2

Worked example 2

Find ∫lnxd⁢x for x>0.

  1. Choose u=ln x, dv=dx.
  2. Then u⁢v−∫v⁢d⁢u=xlnx−∫1d⁢x.
xlnx−x+C.

Check your understanding

For ∫xcosxd⁢x, choose u and dv.

Show answer

u=x, d⁢v=cosxd⁢x.

Differentiating x simplifies it, while cosine is easy to integrate.

03 / WORKSHEET

Your turn

6 questions · 12 marks · Work at your own pace.

Read the questions online
  1. Find ∫xcosxd⁢x.
    2 marks
  2. Find ∫xsin2⁢xd⁢x.
    2 marks
  3. Find ∫x2exd⁢x.
    2 marks
  4. Find ∫xlnxd⁢x for x>0.
    2 marks
  5. Evaluate ∫01xexd⁢x.
    2 marks
  6. Find ∫arctanxd⁢x.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find ∫xcosxd⁢x.
    2 marks

    Use u=x, v=sin x.

    Subtract the integral of sin x.

    xsinx+cosx+C.
  2. Find ∫xsin2⁢xd⁢x.
    2 marks

    Use v=-cos2x/2.

    Integrate the remaining cosine term.

    −xcos2⁢x⁢/2+sin2⁢x⁢/4+C.
  3. Find ∫x2exd⁢x.
    2 marks

    Apply parts with u=x squared.

    Apply parts again to the remaining x exp(x) term.

    ex(x2−2⁢x+2)+C.
  4. Find ∫xlnxd⁢x for x>0.
    2 marks

    Use u=ln x, dv=x dx.

    The remaining integral is x/2.

    (x2/2)lnx−x2/4+C.
  5. Evaluate ∫01xexd⁢x.
    2 marks

    Use antiderivative (x-1)exp(x).

    The endpoint values are 0 and -1.

    1.
  6. Find ∫arctanxd⁢x.
    2 marks

    Use u=arctan x, dv=dx.

    The remaining integral is x/(1+x squared).

    xarctanx−12ln(1+x2)+C.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Specialist Mathematics integration techniques and applications, including inverse-trigonometric patterns, substitution, parts, simple partial fractions, areas and solids of revolution.

Official curriculum source ↗
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