ASCENTLEARNING
Join a weekly class
Skip to learning content
Year 12 · Integration techniques and applications · 22 min

Selecting/combining methods

Choose and combine techniques based on structure rather than surface appearance.

01 / LEARN

The idea, step by step

Ask what differentiation would create

Before calculating, identify a derivative pattern: an inner expression with its derivative suggests substitution; a product that simplifies under differentiation suggests parts; a rational expression may need division or partial fractions.

A square-completion step can reveal an inverse-trigonometric pattern. For example, x2+6⁢x+13=(x+3)2+4. Algebraic preparation is part of integration, not a different problem.

Explain why a method fits

Different correct methods can give antiderivatives that differ by a constant. A derivative check tests equivalence more reliably than comparing their appearance. For definite integrals, also check the integrand's sign and the rough size of the answer.

Do not force integration by parts onto every product. In x exp(x squared), the x is already proportional to the derivative of the inner exponent, so substitution is shorter. Combining methods is useful only when each stage actually simplifies the remaining task.

A common trap

Every product requires integration by parts.

Instead: First check for a reverse chain-rule pattern, which may be simpler.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example 1

Choose a method and find ∫xex2d⁢x.

  1. The factor x matches the derivative of x squared up to a constant.
  2. Use u=x squared, rather than parts.
ex2/2+C.
Example 2

Worked example 2

Integrate 1⁢/⁢(x2+6⁢x+13).

  1. Complete the square: denominator=(x+3) squared+4.
  2. Use the scaled arctangent rule.
12arctan((x+3)⁢/2)+C.

Check your understanding

Which is shorter for integral ln x / x?

Show answer

Substitution u=ln x.

The factor dx/x is exactly du.

03 / WORKSHEET

Your turn

6 questions · 12 marks · Work at your own pace.

Read the questions online
  1. Integrate lnx⁢/⁢x for x>0.
    2 marks
  2. Integrate x⁢/1−x2 on -1<x<1.
    2 marks
  3. Integrate xe2⁢x.
    2 marks
  4. Integrate cos2xsinx.
    2 marks
  5. Explain whether x exp(x squared) and x exp(x) should use the same first method.
    2 marks
  6. Verify that ex(x2−2⁢x+2) integrates x2ex.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Integrate lnx⁢/⁢x for x>0.
    2 marks

    Set u=ln x.

    Integrate u du.

    (lnx)2/2+C.
  2. Integrate x⁢/1−x2 on -1<x<1.
    2 marks

    Use u=1-x squared.

    Then x dx=-du/2.

    −1−x2+C.
  3. Integrate xe2⁢x.
    2 marks

    Use parts with u=x and v=exp(2x)/2.

    Subtract the remaining exponential integral.

    e2⁢x(x⁢/2−1⁢/4)+C.
  4. Integrate cos2xsinx.
    2 marks

    Use u=cos x.

    The negative differential changes the sign.

    −cos3x⁢/3+C.
  5. Explain whether x exp(x squared) and x exp(x) should use the same first method.
    2 marks

    The derivative of x squared supplies the first factor x.

    Differentiating x simplifies the second product without such a match.

    No. Substitution is efficient for the first; parts is efficient for the second.
  6. Verify that ex(x2−2⁢x+2) integrates x2ex.
    2 marks

    Differentiate by the product rule.

    The bracket sum simplifies to x squared.

    It does.
Checking saved progress…

Continue learning

Definite integration

Next lesson
Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Specialist Mathematics integration techniques and applications, including inverse-trigonometric patterns, substitution, parts, simple partial fractions, areas and solids of revolution.

Official curriculum source ↗
Back to Integration techniques and applications

Save your next step.

Create a free account to save your learning progress. Lessons and downloads stay free, with or without an account.

Create free account