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Year 12 · Integration techniques and applications · 22 min

Trigonometric identities in integration

Rewrite trigonometric integrands using identities before integrating.

01 / LEARN

The idea, step by step

Make the integrand integrable

Power-reduction identities give sin2x=(1−cos2⁢x)⁢/2 and cos2x=(1+cos2⁢x)⁢/2. Integrate the rewritten sum and remember the inner frequency in the antiderivative.

For an odd sine power, keep one sin x factor and replace the remaining sin squared using 1-cos squared. Then u=cos x absorbs the single sine factor, with a negative differential. A similar strategy works for odd cosine powers.

Select an identity for the task

Products can be rewritten as sums, for example sinxcosx=sin2⁢x⁢/2. When two different frequencies occur, a product-to-sum identity may produce two simple terms. Check signs by testing a convenient angle.

Do not replace a squared sine by half a sine. An identity must be true for every x in the relevant domain. Differentiate the final antiderivative and simplify with the same identity to verify equivalence.

A common trap

The antiderivative of sin squared is obtained by applying the power rule directly to sin.

Instead: The power rule applies to powers of the integration variable; a composite expression needs a chain-rule factor or an identity.

02 / WORKED EXAMPLES

See the thinking

Example 1

Worked example 1

Find ∫sin2xd⁢x.

  1. Use sin2x=(1−cos2⁢x)⁢/2.
  2. Integrate the constant and cosine terms separately.
x⁢/2−sin2⁢x⁢/4+C.
Example 2

Worked example 2

Find ∫sin3xd⁢x.

  1. Write the integrand as (1−cos2x)sinx.
  2. Use u=cos x, so du=-sin x dx.
−cosx+cos3x⁢/3+C.

Check your understanding

Rewrite sin squared x times cos squared x.

Show answer

(1−cos4⁢x)⁢/8.

Use sin x cos x=sin 2x/2, then reduce the square.

03 / WORKSHEET

Your turn

6 questions · 12 marks · Work at your own pace.

Read the questions online
  1. Find ∫cos2(2⁢x)d⁢x.
    2 marks
  2. Find ∫sinxcosxd⁢x.
    2 marks
  3. Find ∫sin2xcos2xd⁢x.
    2 marks
  4. Evaluate ∫0π⁢/2sin2xd⁢x.
    2 marks
  5. Find ∫sinxcos(3⁢x)d⁢x.
    2 marks
  6. Find ∫cos3xd⁢x.
    2 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find ∫cos2(2⁢x)d⁢x.
    2 marks

    Use (1+cos4⁢x)⁢/2.

    Divide the cosine antiderivative by its frequency 4.

    x⁢/2+sin4⁢x⁢/8+C.
  2. Find ∫sinxcosxd⁢x.
    2 marks

    Use u=sin x.

    Integrate u du.

    sin2x⁢/2+C.
  3. Find ∫sin2xcos2xd⁢x.
    2 marks

    Rewrite as (1−cos4⁢x)⁢/8.

    Integrate each term.

    x⁢/8−sin4⁢x⁢/32+C.
  4. Evaluate ∫0π⁢/2sin2xd⁢x.
    2 marks

    Use x⁢/2−sin2⁢x⁢/4.

    The sine endpoint terms are zero.

    π⁢/4.
  5. Find ∫sinxcos(3⁢x)d⁢x.
    2 marks

    Use sinxcos3⁢x=(sin4⁢x−sin2⁢x)⁢/2.

    Integrate both terms with their frequencies.

    −cos4⁢x⁢/8+cos2⁢x⁢/4+C.
  6. Find ∫cos3xd⁢x.
    2 marks

    Write (1−sin2x)cosx.

    Use u=sin x.

    sinx−sin3x⁢/3+C.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 2 Specialist Mathematics integration techniques and applications, including inverse-trigonometric patterns, substitution, parts, simple partial fractions, areas and solids of revolution.

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