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Year 11 · Complex numbers · 18 min

Vector interpretation of addition and conjugation

Use complex addition, subtraction and conjugation as precise geometric operations.

01 / LEARN

The idea, step by step

Addition is a two-component translation

Writing z=a+b⁢i as vector (a,b) makes complex addition identical to component vector addition. The point z+w can be found by placing the displacement for w at the end of the vector for z.

Subtracting w means adding the opposite displacement. The vector from point A to point B is always B−A, not A−B.

Conjugation and real scalar multiplication

Conjugation reflects in the real axis, so it preserves lengths and horizontal coordinates. Applying it twice returns the original number: z¯¯=z.

Multiplication by a real k scales both components. A positive k preserves direction; a negative k also reverses direction. It scales distances from the origin by ∣⁢k⁢∣. These facts let you check component calculations geometrically.

A common trap

Calling conjugation a reflection in the imaginary axis.

Instead: Conjugation leaves the real coordinate unchanged and reverses the imaginary coordinate, so the mirror is the real axis.

02 / WORKED EXAMPLES

See the thinking

Example 1

Add using two representations

Let u=2+i and v=−1+3⁢i. Find u+v and describe its construction.

  1. Add components: (2−1)+(1+3)⁢i=1+4⁢i.
  2. Start at (2,1) and move (−1,3) to reach (1,4).
  3. The origin and this endpoint form the resultant vector.
u+v=1+4⁢i.
Example 2

Find a reflected midpoint

Let z=−3+2⁢i. Find the midpoint of the points z and z¯.

  1. The reflected point is z¯=−3−2⁢i.
  2. The midpoint is (z+z¯)⁢/2=(−6)⁢/2=−3.
  3. The midpoint lies on the mirror axis, the real axis.
−3.

Check your understanding

What translation maps z to z+3−2⁢i?

Show answer

Three units right and two units down.

The added complex number is displacement (3,−2).

03 / WORKSHEET

Your turn

6 questions · 18 marks · Work at your own pace.

Read the questions online
  1. Find u+v and u−v for u=3−2⁢i and v=−1+i.
    3 marks
  2. Find the vector from A=−2+i to B=1−3⁢i.
    2 marks
  3. Find the midpoint between 2+5⁢i and −4−i.
    3 marks
  4. Describe the effect of multiplying all complex numbers by −2.
    3 marks
  5. Prove z+z¯ is real and z−z¯ has real part zero for every complex z.
    4 marks
  6. A parallelogram has successive vertices 0, z, z+w, w. For z=4+i and w=−1+2⁢i, find its centre.
    3 marks
Read the worked solutions

Equivalent correct methods earn the corresponding marks. Include units where asked.

  1. Find u+v and u−v for u=3−2⁢i and v=−1+i.
    3 marks

    Add or subtract the two real components and the two imaginary components.

    u+v=2−i; u−v=4−3⁢i.
  2. Find the vector from A=−2+i to B=1−3⁢i.
    2 marks

    B−A=(1−3⁢i)−(−2+i)=3−4⁢i.

    3−4⁢i.
  3. Find the midpoint between 2+5⁢i and −4−i.
    3 marks

    Average components: (2−4)⁢/2=−1 and (5−1)⁢/2=2.

    −1+2⁢i.
  4. Describe the effect of multiplying all complex numbers by −2.
    3 marks

    Both coordinates double in magnitude and reverse sign.

    A dilation by factor 2 about the origin followed by a half-turn.
  5. Prove z+z¯ is real and z−z¯ has real part zero for every complex z.
    4 marks

    Write the conjugate as a−b⁢i.

    Add and subtract componentwise; each result has the required zero component.

    If z=a+b⁢i, the expressions are 2⁢a and 2⁢b⁢i. The second is pure imaginary when b≠0, and is zero when b=0.
  6. A parallelogram has successive vertices 0, z, z+w, w. For z=4+i and w=−1+2⁢i, find its centre.
    3 marks

    The opposite vertices 0 and z+w=3+3⁢i have midpoint (3+3⁢i)⁢/2.

    Diagonals of a parallelogram share their midpoint.

    32+32i.
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Curriculum reference & lesson scope

SACE Board of South Australia

Stage 1 Mathematics, real and complex numbers: Cartesian arithmetic, conjugates, quadratic roots and Argand geometry. Polar form and roots of unity are developed in Year 12.

Official curriculum source ↗
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